Odpowiedź:
[tex] {( \frac{1}{3} )}^{2} + {2}^{ - 3} - 16 \frac{3}{4} = \frac{1}{9} + \frac{1}{8} - \frac{67}{4} = [/tex]
[tex] = \frac{8}{72} + \frac{9}{72} - \frac{1206}{72} = \frac{17}{72} - \frac{1206}{72} = - \frac{1189}{72}[/tex]
[tex] = - \frac{1189}{72} = - 16 \frac{37}{72} [/tex]