Odpowiedź:
[tex] \frac{ {2}^{15} }{ {3}^{11} } \cdot \frac{81}{ {16}^{2} } = \frac{ {2}^{15} }{ {3}^{11} } \cdot \frac{ {3}^{4} }{( {2}^{4} {)}^{2} } = \frac{ {2}^{15} }{ {3}^{11} } \cdot \frac{ {3}^{4} }{ {2}^{8} } = \frac{ {2}^{7} }{ {3}^{7} } = ( \frac{2}{3} {)}^{7} [/tex]
