Odpowiedź:
[tex]\begin{cases}9x-2y=5\\3x+y=-1\ \ /\cdot2\end{cases}\\\\\\+\begin{cases}9x-2y=5\\6x+2y=-2\end{cases}\\---------\\15x=3\ \ /:15\\\\x=\frac{3}{15}\\\\x=\frac{1}{5}\\\\\\3\cdot\frac{1}{5}+y=-1\\\\\frac{3}{5}+y=-1\\\\y=-1-\frac{3}{5}\\\\y=-\frac{8}{5}\\\\\begin{cases}x=\frac{1}{5}\\y=-\frac{8}{5}\end{cases}[/tex]
