Dane:
[tex]a=6\\H=6[/tex]
1. Pole podstawy.
[tex]P_p=6\cdot\frac{a^2\sqrt{3}}{4}\\P_p=6\cdot\frac{6^2\sqrt{3}}{4}=P_p=6\cdot\frac{36\sqrt{3}}{4}=6\cdot9\sqrt{3}=54\sqrt{3}[/tex]
2. Pole boczne.
[tex]P_s-\mbox{pole jednej sciany}\\P_b=6P_s=6aH=6\cdot6\cdot6=216[/tex]
3. Pole całkowite.
[tex]P_c=2P_p+P_b\\P_c=2\cdot54\sqrt{3}+216=108\sqrt{3}+216[/tex]
4. Objętość.
[tex]V=P_pH\\V=54\sqrt{3}\cdot6=324\sqrt{3}[/tex]
