Odpowiedź:
[tex]q=\dfrac{a_2}{a_1}=\dfrac{\sqrt{3}}{\sqrt{2}}=\dfrac{\sqrt{3}}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\boxed{\dfrac{\sqrt{6}}{2}}[/tex]
[tex]a_3=a_2\cdot q=\sqrt{3}\cdot\dfrac{\sqrt{6}}{2}=\boxed{\dfrac{3\sqrt{2}}{2}}\\\\a_4=a_3\cdot q=\dfrac{3\sqrt{2}}{2}\cdot \dfrac{\sqrt{6}}{2}=\boxed{\dfrac{3\sqrt{3}}{2}}\\\\a_5=a_4\cdot q=\dfrac{3\sqrt{3}}{2}\cdot \dfrac{\sqrt{6}}{2}=\boxed{\dfrac{9\sqrt{2}}{4}}[/tex]
