Odpowiedź:
[tex]\frac{3x^2-6x}{4x^2-9}\\\\4x^2-9\neq 0\\\\(2x-3)(2x+3)\neq 0\\\\2x-3\neq 0\ \ \ \ \ \ i\ \ \ \ 2x+3\neq 0\\\\2x\neq 3\ \ /:2\ \ \ \ i\ \ \ \ 2x\neq -3\ \ /:2\\\\x\neq \frac{3}{2}\ \ \ \ \ \ \ \ \ \ \ \ i\ \ \ \ x\neq -\frac{3}{2}\\\\D=R\setminus\left\{-\frac{3}{2},\frac{3}{2}\right\}[/tex]
[tex]f(-3)=\dfrac{3\cdot(-3)^2-6\cdot(-3)}{4\cdot(-3)^2-9}=\dfrac{3\cdot9+18}{4\cdot9-9}=\dfrac{27+18}{36-9}=\dfrac{45}{27}=\dfrac{5}{3}=1\dfrac{2}{3}\\\\\\\\f(1)=\dfrac{3\cdot1^2-6\cdot1}{4\cdot1^2-9}=\dfrac{3\cdot1-6}{4\cdot1-9}=\dfrac{3-6}{4-9}=\dfrac{-3}{-5}=\dfrac{3}{5}\\\\\\\\f(3)=\dfrac{3\cdot3^2-6\cdot3}{4\cdot3^2-9}=\dfrac{3\cdot9-18}{4\cdot9-9}=\dfrac{27-18}{36-9}=\dfrac{9}{27}=\dfrac{1}{3}[/tex]
