Odpowiedź:
Wzór na twierdzenie pitagorasa:
[tex] {x}^{2} + {y}^{2} = {z}^{2} [/tex]
[tex] {5}^{2} + {7}^{2} = {x}^{2} \\ 25 + 49 = {x}^{2} \\ x = \sqrt{74} [/tex]
[tex] {2}^{2} + ({2 \sqrt{37}) }^{2} = {x}^{2} \\ 4 + 148 = {x}^{2} \\ x = \sqrt{152} = 2 \sqrt{38} [/tex]
[tex] {7}^{2} + {z}^{2} = {10}^{2} \\ {z}^{2} = 100 - 49 \\ z = \sqrt{51} [/tex]
