Odpowiedź:
[tex]\frac{x-3}{x-2}=\frac{x+3}{x+1}\\\\Zalo\.zenia\\\\x-2\neq 0\ \ \ \ i\ \ \ \ x+1\neq 0\\\\x\neq 2\ \ \ \ \ \ \ \ i\ \ \ \ x\neq -1\\\\D=R\setminus\left\{-1,2\right\}\\\\\\\frac{x-3}{x-2}=\frac{x+3}{x+1}\ \ \ \ (mno\.zymy\ \ na\ \ krzy\.z)\\\\(x-3)(x+1)=(x+3)(x-2)\\\\x^2+x-3x-3=x^2-2x+3x-6\\\\x^2-2x-3=x^2+x-6\\\\x^2-2x-x^2-x=-6+3\\\\-2x-x=-3\\\\-3x=-3\ \ /:(-3)\\\\x=1[/tex]
