[tex]3(2-x) + 2 = 3-\frac{1}{2}(x+1) \ \ \ |\cdot2\\\\6(2-x) + 4 = 6-(x+1)\\\\12 - 6x + 4 = 6-x-1\\\\-6x+16 = -x+5\\\\-6x+x = 5-16\\\\-5x= -11 \ \ \ |:(-5)\\\\\boxed{x = \frac{11}{5} = 2\frac{1}{5}}[/tex]
