rozwiaz uklad rownan metoda podstawiania
3(2x-y)-2(x+4y)=6-10y
0,5(x-3y)-(4y-x)+8=0


Odpowiedź :

[tex]\left \{ {{3(3x-y)-2(x+4y)=6-10y} \atop {0.5(x-3y)-(4y-x)+8=0}} \right. \\\left \{ {{9x-3y-2x-8y=6-10y} \atop {\frac12x-\frac32y-4y+x+8=0}} \right. \\\left \{ {{7x-y=6} \atop {\frac32x-\frac{11}2y=-8 /*2}} \right. \\\left \{ {{7x-6=y} \atop {3x-11y=-16}} \right. \\\left \{ {{y=7x-6} \atop {3x-11(7x-6)=-16}} \right.[/tex]

[tex]\left \{ {{y=7x-6} \atop {3x-77x+66=-16}} \right. \\\left \{ {{y=7x-6} \atop {-74x=-82 /:(-74)}} \right. \\\left \{ {{y=7x-6} \atop {x=\frac{41}{37}}} \right. \\\left \{ {{y=7*\frac{41}{37}-6} \atop {x=\frac{41}{37}}} \right. \\\left \{ {{y=\frac{65}{37}} \atop {x=\frac{41}{37}}} \right.[/tex]