[tex]Dane:\\V = 3 \ cm\times 4 \ cm\times 6 \ cm = 72 \ cm^{3} = 0,000072 \ m^{3}\\d = 1025\frac{kg}{m^{3}}\\g = 10\frac{m}{s^{2}}\\Szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\F_{w} = d\cdot g\cdot V\\\\F_{w} = 1025\frac{kg}{m^{3}}\cdot10\frac{m}{s^{2}}\cdot0,000072 \ m^{3}\\\\\boxed{F_{w} = 0,738 \ N}[/tex]
