Odpowiedź:
[tex]a)\ \ (3ab^2)^3=3^3\cdot a^3\cdot(b^2)^3=27a^3b^6\\\\\\b)\ \ (\frac{1}{2}a^2b^3)^4=(\frac{1}{2})^4\cdot(a^2)^4\cdot(b^3)^4=\frac{1}{16}a^8b^1^2\\\\\\c)\ \ \left (\dfrac{2ab^5}{c^2}\right)^2=\dfrac{(2ab^5)^2}{(c^2)^2}=\dfrac{2^2\cdot a^2\cdot(b^5)^2}{c^4}=\dfrac{4a^2b^1^0}{c^4}\\\\\\d)\ \ \left(\dfrac{a^5b^6}{3x^2}\right)^5=\dfrac{(a^5b^6)^5}{(3x^2)^5}=\dfrac{(a^5)^5\cdot(b^6)^5}{3^5\cdot(x^2)^5}=\dfrac{a^2^5b^3^0}{243x^1^0}[/tex]