zapisz w postaci jednej potęgi:
a(4²)⁵*(4⁴)³
b.(6⁸)³:(6³)⁵
c.((½)³)³*((½)⁴)⁴
d.(0,7⁴)⁹:(0,7⁵)⁶
help na teraz ​


Odpowiedź :

a)

[tex](4^{2})^{5} * (4^{4})^{3} = 4^{10} * 4^{12} = 4^{22}[/tex]

b)

[tex](6^{8})^{3} : (6^{3})^{5} = 6^{24} : 6^{15} = 6^{9}[/tex]

c)

[tex]((\frac{1}{2})^{3})^{3} * ((\frac{1}{2})^{4})^{4} = (\frac{1}{2})^{9} * (\frac{1}{2})^{16} = (\frac{1}{2})^{25}[/tex]

d)

[tex](0,7^{4})^{9} : (0,7^{5})^{6} = (0,7)^{36} : (0,7)^{30} = (0,7)^{6}[/tex]

Cześć!

Szczegółowe wyjaśnienie:

Zapisz w postaci jednej potęgi.

a)

[tex](4 {}^{2} ) {}^{5} \cdot(4 {}^{4} ) {}^{3} = 4 {}^{10} \cdot4 {}^{12} = 4 {}^{10 + 12} = 4 {}^{22} [/tex]

b)

[tex](6 {}^{8} ) {}^{3} : (6 {}^{3} ) {}^{5} = 6 {}^{24} : 6 {}^{15} = 6 {}^{24 - 15} = 6 {}^{9} [/tex]

c)

[tex](( \frac{1}{2} ) {}^{3} ) {}^{3} \cdot(( \frac{1}{2} ) {}^{ 4} ) {}^{4} = ( \frac{1}{2} ) {}^{9} \cdot (\frac{1}{2} ) {}^{16} =( \frac{1}{2} ) {}^{9 + 16} = ( \frac{1}{2} ) {}^{25} = \frac{1}{2 {}^{25} } [/tex]

d)

[tex](0.7 {}^{4} ) {}^{9} : (0.7 {}^{5} ) {}^{6} = 0.7 {}^{9\cdot4} : 0.7 {}^{5 \cdot6} = 0.7 {}^{36} : 0.7 {}^{30} = 0.7 {}^{36 - 30} = 0.7 {}^{6} = ( \frac{7}{10} ) {}^{6} = \frac{7 {}^{6} }{10 {}^{6} } [/tex]