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PROSZĘ NA DZIŚ, 7 KLASA,,,, ​

PROSZĘ NA DZIŚ 7 KLASA class=

Odpowiedź :

Odpowiedź:

a)2³·5=8·5=40

b)3³·2=27·2=54

c)[tex]\frac{6}{27}[/tex]=[tex]\frac{2}{9}[/tex]

d)[tex]\frac{4}{8}[/tex]=[tex]\frac{1}{2}[/tex]

e)[tex]\frac{27}{15}[/tex]=[tex]\frac{9}{5}[/tex]=[tex]1\frac{4}{5}[/tex]

f)[tex]\frac{1}{8*5}[/tex]=[tex]\frac{1}{40}[/tex]

Agulka1987viz

Odpowiedź:

[tex]a) \: \:( 2 \sqrt[3]{5} {)}^{3} = {2}^{3} \times ( \sqrt[3]{5} {)}^{3} = 8 \times 5 = 4 \\ b) \: \: (3 \sqrt[3]{2} {)}^{3} = {3}^{3} \times (\sqrt[3]{2} {)}^{3} = 27 \times 2 = 54 \\ c) \: \: ( \frac{ \sqrt[3]{6} }{3} {)}^{3} = \frac{( \sqrt[3]{6} )^{3} }{ {3}^{3} } = \frac{6}{27} = \frac{2}{9} [/tex]

[tex]d) \: \: ( \frac{ \sqrt[3]{4} }{2} {)}^{3} = \frac{( \sqrt[3]{4} {)}^{3} }{ {2}^{3} } = \frac{4}{8} = \frac{1}{2} \\ e) \: \: ( \frac{3}{ \sqrt[3]{15} } {)}^{3} = \frac{ {3}^{3} }{( \sqrt[3]{15} {)}^{3} } = \frac{27}{15} = \frac{9}{5} \\ f) \: \: ( \frac{1}{2 \sqrt[3]{5} } {)}^{3} = \frac{1}{ {2}^{3} \times ( \sqrt[3]{5} {)}^{3} } = \frac{1}{8 \times 5} = \frac{1}{40} [/tex]