[tex]Dane:\\m_1 = m_2 = 4 \ t = 4 \ 000 \ kg = 4\cdot10^{3} \ kg\\r_1 = 10 \ m\\r_2 = 30 \ m = 3r_1\\G = 6,67\cdot10^{-11} \ \frac{N\cdot m^{2}}{kg^{2}}\\Szukane:\\\frac{F_1}{F_2} = ?\\\\Rozwiazanie\\\\F =G\cdot\frac{m_1\cdot m_2}{r^{2}}[/tex]
[tex]F_1 = G\cdot\frac{m_1\cdot m_2}{r_1^{2}}\\\\F_2 = G\cdot\frac{m_1\cdot m_2}{r_2^{2}} = G\cdot\frac{m_1\cdot m_2}{(3r_1)^{2}} = G\cdot\frac{m_1\cdot m_2}{9r_1^{2}}\\\\\frac{F_1}{F_2} = \frac{\frac{G\cdot m_1m_2}{r_1^{2}}}{\frac{G\cdot m_1m_2}{9r_1^{2}}} = 9\\\\F_2 = \frac{1}{9}F_1[/tex]
Odp. Siła przyciągania zmaleje 9 razy.
