[tex]Dane:\\m = 100 \ kg\\h = 200 \ m\\g = 10\frac{m}{s^{2}} = 10\frac{N}{kg}\\Szukane:\\\Delta E_{p} = ?\\\\Rozwiazanie\\\\\Delta E_{p} = m\cdot g\cdot h\\\\\Delta E_{p} =100 \ kg \cdot 10\frac{N}{kg}\cdot 200 \ m\\\\\boxed{\Delta E_{p} = 200 \ 000 \ J = 200 \ kJ}\\\\(1 \ kJ = 1000 \ J)[/tex]
Odp. Energia potencjalna grawitacji wzrosła o 200 kJ.
