Odpowiedź:
[tex] \frac{ {6}^{10} }{ {2}^{10} } = ( \frac{6}{2} {)}^{10} = {3}^{10} \\ \\ \\ ( \frac{1}{3} {)}^{22} \times {9}^{22} = ( {3}^{ - 1} {)}^{22} \times ( {3}^{2} {)}^{22} = {3}^{ - 22} \times {3}^{44} = {3}^{22} [/tex]
