Odpowiedź:
[tex]a)\ \ \dfrac{\not3^1\sqrt{5}}{\not15_{5}}=\dfrac{\sqrt{5}}{5}\\\\\\b)\ \ \dfrac{4\sqrt{6}}{10\sqrt{6}}=\dfrac{4}{10}=\dfrac{2}{5}\\\\\\c)\ \ \dfrac{4+2\sqrt[3]{3}}{2}=\dfrac{\not2(2+\sqrt[3]{3})}{\not2}=2+\sqrt[3]{3}\\\\\\d)\ \ \dfrac{-6+18\sqrt[3]{5}}{-6}=-\dfrac{-6+18\sqrt[3]{5}}{6}=-\dfrac{\not6(-1+3\sqrt[3]{5})}{\not6}=-(-1+3\sqrt[3]{5})=1-3\sqrt[3]{5}[/tex]
