Odpowiedź:
[tex] log1 = log {10}^{0} = 0 \\ log_{2} \frac{1}{16} = log_{2} {2}^{ - \frac{1}{4} } = - \frac{1}{4} \\ log_{5}25 \sqrt[3]{5} = log_{5}( {5}^{2} \cdot \: {5}^{ \frac{1}{3} } ) = log_{5} {5}^{\frac{7}{3}} = \frac{7}{3}[/tex]
