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Zadanie 5 potrzebuje na szybko

Zadanie 5 Potrzebuje Na Szybko class=

Odpowiedź :

LoczeeQviz

a)

[tex] \sqrt{a} = 7 | {}^{2} \\ a = 49[/tex]

b)

[tex] \sqrt{b} = 100 | {}^{2} \\ b = 10000[/tex]

c)

[tex] \sqrt{c} = \frac{2}{5} | {}^{2} \\ c = \frac{4}{25} [/tex]

d)

[tex] \sqrt{d} = 1 | {}^{2} \\ d = 1[/tex]

e)

[tex] \sqrt[3]{e} = 3 | {}^{3} \\ e = 27[/tex]

f)

[tex] \sqrt[3]{f} = - \frac{1}{2} | {}^{3} \\ f = - \frac{1}{8} [/tex]

g)

[tex] \sqrt[3]{g} = 0 | {}^{3} \\ g = 0[/tex]

h)

[tex] \sqrt[3]{h} = - 0.1 | {}^{3} \\ h = - 0.001[/tex]

Magdaviz

Odpowiedź:

[tex]a)\\\\ \sqrt{a}=7\\\\(\sqrt{a})^2=7^2\\\\a=49\\\\\sqrt{49}=7\\\\\\b)\\\\\sqrt{b}=100\\\\(\sqrt{b})^2=100^2\\\\b=10000\\\\\sqrt{10000}=100\\\\\\c)\\\\\sqrt{c}=\frac{2}{5}\\\\(\sqrt{c})^2=(\frac{2}{5})^2\\\\c=\frac{4}{25}\\\\\sqrt{\frac{4}{25}}=\frac{2}{5}[/tex]

[tex]d)\\\\\sqrt{d}=1\\\\(\sqrt{d})^2=1^2\\\\d=1\\\\\sqrt{1}=1\\\\\\e)\\\\\sqrt[3]{e}=3\\\\(\sqrt[3]{e})^3=3^3\\\\e=27\\\\\sqrt[3]{27}=3\\\\\\f)\\\\\sqrt[3]{f}=-\frac{1}{2}\\\\(\sqrt[3]{f})^3=(-\frac{1}{2})^3\\\\f=-\frac{1}{8}\\\\\sqrt[3]{-\frac{1}{8}}=-\frac{1}{2}[/tex]

[tex]g)\\\\\sqrt[3]{g}=0\\\\(\sqrt[3]{g})^3=0^3\\\\g=0\\\\\sqrt[3]{0}=0\\\\\\h)\\\\\sqrt[3]{h}=-0,1\\\\(\sqrt[3]{h})^3=(-0,1)^3\\\\h=-0,001\\\\\sqrt[3]{-0,001}=-0,1[/tex]

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