Odpowiedź:
[tex]a) \: \: - 7 {x}^{2} + 42x = 0
x( -7 x + 42) = 0 \\ x = 0 \: \vee \: - 7x + 42 = 0 \\ x = 0 \: \vee \: x = 6[/tex]
[tex]b) \: \: 9 {x}^{2} + \frac{1}{3} \times = 0 \\ x(9x + \frac{1}{3} ) = 0 \\ x = 0 \: \vee9x+ \frac{1}{3} = 0 \\ x = 0 \: \vee \: x = - \frac{1}{27} [/tex]
[tex]c) \: \: 36 {x}^{2} = 6x \\ 36 {x}^{2} - 6x = 0 \\ 6x(6x - 1 ) = 0 \\ x = 0 \: \vee \: 6x - 1 = 0 \\ x = 0 \: \vee \: x = \frac{1}{6} [/tex]
[tex]d) \: \: 2x + 18 {x}^{2} = 0 \\ 2x(1 + 9x) = 0 \\ 2x = 0 \: \vee \: 1 + 9x = 0 \\ x = 0 \: \vee \: x = - \frac{1}{9} [/tex]
[tex] e) \: \: \sqrt{2} {x}^{2} - \sqrt{8} x = 0 \\ \sqrt{2} x(x - \sqrt{4 } )= 0 \\ \sqrt{2} x = 0 \: \vee \: x - 2 = 0 \\ x = 0 \: \vee \: x = 2[/tex]
[tex] f) \: \: \sqrt{3} x = - 3 {x}^{2} \\ \sqrt{3} x + 3 {x}^{2} = 0 \\ x( \sqrt{3} + 3x )= 0 \\ x = 0 \: \vee \: \sqrt{3} + 3 = 0 \\ x = 0 \: \vee \: x = \sqrt{3} [/tex]
