Odpowiedź:
[tex]b) \: \: a = 6 \\ b = \sqrt{11} \\ \\ {h}^{2} = {b}^{2} - ( \frac{1}{2} a {)}^{2} \\ {h}^{2} = ( \sqrt{11 {)}^{2} } - {3}^{2} = 11 - 9 = 2 \\ \\ h = \sqrt{ {h}^{2} } = \sqrt{2} [/tex]
[tex]c) \: \: a = 4 \sqrt{5} \\ b = 9 \\ \\ {h}^{2} = 9^2- { (2 \sqrt{5 {)}^{2} } }^{2} = 81 -20= 61 \\ h = \sqrt{61} [/tex]
[tex]a = 10 \\ b = 2 \sqrt{14} \\ \\ {h}^{2} = (2 \sqrt{14} {)}^{2} -5^2 = 56 -25= 31 \\ \\ h = \sqrt{31} = [/tex]
