Odpowiedź:
[tex](2 \sqrt{2} - 2)^{2} = 8 - 8 \sqrt{2 } + 4 = 12 - 8 \sqrt{2} \\ (4 - \sqrt{2} {)}^{2} = 16 - 8 \sqrt{2} + 2 = 18 - 8 \sqrt{2} \\ ( \sqrt{6 {)}^{2} } = 6 \\ \\ (2 \sqrt{2} - 2 {)}^{2} + ( \sqrt{6} {)}^{2} = (4 - \sqrt{2} {)}^{2} \\ 12 - 8 \sqrt{2 } + 6 = 18 - 8 \sqrt{2} \\18 - 8 \sqrt{2} = 18 - 8 \sqrt{2} \\ {a}^{2} + {b}^{2} = {c}^{2} [/tex]
odp. trójkąt o podanych wymiarach jest prostokątny
