Odpowiedź :
[tex]1.\\\\a = 7 m\\H = 2 m\\Pp = \frac{a^{2}\sqrt{3} }{4} = \frac{7^{2}\sqrt{3} }{4} = \frac{49\sqrt{3} }{4} m^{2} \\\\V = Pp * H = \frac{49\sqrt{3} }{4} * 2 = \frac{49\sqrt{3} }{2} m^{3}[/tex]
[tex]2. \\\\x - krawedz\\\\12x = 4,8dm\\x = 0,4 dm\\\\V= a^{3} = 0,4^{3} = 0,064 dm^{3}[/tex]
[tex]3.\\\\a = 6 cm\\H = 3 cm\\Pp = \frac{a^{2}\sqrt{3} }{4}= \frac{6^{2}\sqrt{3} }{4} = \frac{36\sqrt{3} }{4} = 9\sqrt{3} \\\\V = \frac{1}{3}*Pp*H = \frac{1}{3} * 9\sqrt{3} * 3 = 9\sqrt{3} cm^{3}[/tex]
[tex]4.\\\\a = 3 cm\\H = 8 cm\\\\Pp = a^{2} = 3^{2} = 9 cm^{2} \\\\V = \frac{1}{3}*Pp*H = \frac{1}{3} * 9 * 8 = 24 cm^{3}[/tex]