zad 1
Odp C
A.
[tex]3 = 2(x - 1) \\ x = \frac{5}{2} [/tex]
B.
[tex]2 = 3(x + 1) \\ x = \frac{ - 1}{3} [/tex]
C.
[tex]2 = 3(1 - x) \\ x = \frac{1}{3} [/tex]
D.
[tex]3 = 2(x + 1) \\ x = \frac{1}{2} [/tex]
zad 2
Odp A
A.
[tex] x = - 9 \\ 1 - \frac{ - 9}{3} = 4[/tex]
B.
[tex]x = - 3 \\ 1 - \frac{ - 3}{3} = 2[/tex]
C.
[tex]x = 3 \\ 1 - \frac{3}{3} = 0[/tex]
D.
[tex]x = 9 \\ 1 - \frac{9}{3} = - 2[/tex]
zad 3
Odp D
A.
[tex]x = 2 \\ {2}^{3} - 2 \times {2}^{2} - 2 + 2 = 0[/tex]
B.
[tex]x = 1 \\ {1}^{3} - 2 \times {1}^{2} - 1 + 2 = 0[/tex]
C.
[tex]x = - 1 \\ ( { - 1})^{3} - 2 \times ( { - 1})^{2} - ( - 1) + 2 = 0[/tex]
D.
[tex]x = - 2 \\ ( { - 2})^{3} - 2 \times ( { - 2})^{2} - ( - 2) + 2 = - 12[/tex]
zad 4
Odp D
[tex]3x + 4x + 6x = 39 \\ x = 3 \\ 6 \times 3 = 18[/tex]
zad 5
Odp C
[tex] \frac{1}{m} = \frac{10}{k + n} \\ 1 = \frac{10m}{k + n} \\ k + n = 10m \\ k = 10m - n[/tex]
Mam nadzieję że pomogłam :>
