Zad 5 proszę o rozwiązanie

Odpowiedź:
a)
[tex]\frac{2}{3} + \frac{6}{7} = \frac{14}{21} + \frac{18}{21} = \frac{32}{21} = 1\frac{11}{21}[/tex]
[tex]\frac{7}{8} + \frac{5}{6} = \frac{21}{24} + \frac{20}{24} = \frac{41}{24} = 1\frac{17}{24}[/tex]
b)
[tex]5\frac{1}{4} + \frac{5}{6} = 5\frac{3}{12} + \frac{10}{12} = 5\frac{13}{12} = 6\frac{1}{12}[/tex]
[tex]1 \frac{7}{9} + 2 \frac{3}{10} = 1 \frac{70}{90} + 2 \frac{27}{90} = 3 \frac{97}{90} = 4 \frac{7}{90}[/tex]
[tex]2 \frac{7}{8} + 3 \frac{1}{6} = 2 \frac{21}{24} + \frac{3}{24} = 5 \frac{25}{24} = 6 \frac{1}{24}[/tex]
c)
[tex]\frac{8}{9} - \frac{2}{5} = \frac{40}{45} - \frac{18}{45} = \frac{22}{45}[/tex]
[tex]\frac{7}{8} - \frac{4}{5} = \frac{35}{40} - \frac{32}{40} = \frac{3}{40}[/tex]
[tex]4 \frac{5}{6} - \frac{1}{4} = 4\frac{10}{12} - \frac{3}{12} = 4\frac{7}{12}[/tex]
d)
[tex]6 \frac{8}{9} - 1 \frac{1}{2} = 6\frac{16}{18} - 1\frac{9}{18} = 5\frac{7}{18}[/tex]
[tex]8\frac{5}{7} - 3\frac{2}{5} = 8\frac{25}{35} - 3\frac{14}{35} = 5\frac{11}{35}[/tex]
[tex]4\frac{1}{4} - 4\frac{1}{6} = 4\frac{3}{12} - 4\frac{2}{12} = \frac{1}{12}[/tex]
Szczegółowe wyjaśnienie:
- obliczamy skracamy (jeśli to potrzebne i mamy wnik
Myśle że pomogłem, Miłego dnia
Pozdrawiam :)