Odpowiedź:
[tex]\left(\dfrac{16}{17}\right)^4\cdot\left(\dfrac{34}{32}\right)^4=\left(\dfrac{16}{17}\cdot\dfrac{34}{32}\right)^4=\left(\dfrac{\not16^1}{\not17_{1}}\cdot\dfrac{\not17^1}{\not16_{1}}\right)^4=1^4=1[/tex]
