Odpowiedź:
a)
[tex]pc = 2 \times pp + 3 \times pb = 2 \times \frac{ {a}^{2} \sqrt{3} }{4} + 3ah = \frac{ {8}^{2} \sqrt{3} }{2} + 3 \times 8 \times 10 = 32 \sqrt{3} + 240 = 16(2 \sqrt{3} + 15) \: {cm}^{2} [/tex]
[tex]v = pp \times h = \frac{ {a}^{2} \sqrt{3} }{4} \times h = \frac{ {8}^{2} \sqrt{3} }{4} \times 10 = 160 \sqrt{3} \: {cm}^{3} [/tex]
b)
[tex]pc = 2 {a}^{2} + 4ah = 2 \times {8}^{2} + 4 \times 8 \times 10 = 128 + 320 = 458 {cm}^{2} [/tex]
[tex]v = {a}^{2} \times h = {8}^{2} \times 10 = 640 \: {cm}^{3} [/tex]
c)
[tex]pc = 2 \times \frac{ {6a}^{2} \sqrt{3} }{4} + 6ah = 3 \times {8}^{2} \sqrt{3} + 6 \times 8 \times 10 = 192 \sqrt{3} + 480 =96 ( 2\sqrt{3} + 5) \: {cm}^{2} [/tex]
[tex]v = \frac{3 \times {8}^{2} \sqrt{3} }{2} \times 10 = 320 \sqrt{3} \: {cm}^{3} [/tex]
