Odpowiedź :
zad 5
a) P₁ = 4 · 4 = 16
P₂ = 8 · 3 = 24
P = 24 + 16 = 40
b) P₁ = 4 · 2 = 8
P₂ = 2 · 10 = 20
P = 8 + 20 = 28
C) P₁ = 2 · 6 = 12
P₂ = 2 · 4 = 8
P₃ = 2 · 2 = 4
P = 12 + 8 + 4 = 24
Figura 1) P = 40cm^2
[tex]Pc=P_{1-kwadratu1} +P_{2-prostokata}=a^2+ab=4^2cm+3cm*8cm=16cm^2+24cm^2=40cm^2[/tex]
Figura 2) P = 28cm^2
[tex]Pc=P_{1-prostokata} +P_{2-prostokata}=ab+ab=4cm*2cm+2cm*10cm=8cm^2+20cm^2=28cm^2[/tex]
Figura 3) P = 24cm^2[tex]Pc=P_{1-(prostokata)} +P_{2-(prostokata)}+P_{3-(kwadratu)}=ab+ab+a^2=2cm*6cm+2cm*4cm+2^2cm=12cm^2+8cm^2+4cm^2=24cm^2[/tex]