Odpowiedź:
Szczegółowe wyjaśnienie:
tg α = 4√3 = 4√3/1 = b/a to b = 4√3 to a = 1 to
przeciwprostokątna c² = a² + b²
to c² = 1² + (4√3)² = 1 + 16•3 = 1 + 48 = 49 to c² = 49 /√ to
√c² = √49 to c = 7 to sin α = b/c = 4√3/7 to cos α = a/c = 1/7
√3+sin alfa/ 1+cos alfa = (√3+sin α)/(1+cos α) =
= (√3 + 4√3/7)/(1 + 1/7) = √3(1 + 4/7)/(1 + 1/7) =
= √3(7/7 + 4/7)/(7/7 + 1/7) = √3(11/7)/(8/7) = √3(11/7)•(7/8) =
= √3(11/8) = 11√3/8
