Odpowiedź:
[tex]a)\ \ 25\cdot5^3\cdot5^0=5^2\cdot5^3\cdot5^0=5^{2+3+0}=5^5\\\\\\b)\ \ \frac{1}{81}\cdot\frac{1}{9}\cdot(\frac{1}{3})^7=(\frac{1}{3})^4\cdot(\frac{1}{3})^2\cdot(\frac{1}{3})^7=(\frac{1}{3})^{4+2+7}=(\frac{1}{3})^1^3\\\\\\c)\ \ \dfrac{9\cdot3^9\cdot27}{3^7:3^4}=\dfrac{3^2\cdot3^9\cdot3^3}{3^{7-4}}=\dfrac{3^{2+9+3}}{3^3}=\dfrac{3^1^4}{3^3}=3^{14-3}=3^{11}\\\\\\d)\ \ \dfrac{7^1^1:49}{7^4\cdot7^3}=\dfrac{7^1^1:7^2}{7^{4+3}}=\dfrac{7^{11-2}}{7^7}=\dfrac{7^9}{7^7}=7^{9-7}=7^2[/tex]
