Odpowiedź:
[tex]Zad.14\\\\a)\ \ 3\frac{1}{7}+5\frac{4}{7}-1\frac{6}{7}=8\frac{5}{7}-1\frac{6}{7}=7\frac{12}{7}-1\frac{6}{7}=6\frac{6}{7}\\\\b)\ \ 4-(5\frac{1}{3}-2\frac{2}{3})=4-(4\frac{4}{3}-2\frac{2}{3})=4-2\frac{2}{3}=3\frac{3}{3}-2\frac{2}{3}=1\frac{1}{3}[/tex]
3 i 1/7 + 5 i 4/7 - 1 i 6/7 = 8 i 5/7 - 1 i 6/7 = 7 i 12/7 - 1 i 6/7 = 6 i 6/7
4 - (5 i 1/3 - 2 i 2/3) = 4 - (4 i 4/3 - 2 i 2/3) = 4 - 2 i 2/3 = 3 i 3/3 - 2 i 2/3 = 1 i 1/3
