Odpowiedź :
[tex]1\frac{4}{8} +\frac28=1\frac68=1\frac{3}{4} \\\\\frac6{11}-\frac{3}{11}=\frac{3}{11}\\\\3\frac47*\frac25=\frac{25}7*\frac25=\frac57*\frac21=\frac{10}7=1\frac37[/tex]
[tex]1 \frac{4}{8} + \frac{2}{8} = 1 \frac{6}{8} = 1 \frac{3}{4} [/tex]
[tex] \frac{6}{11} - \frac{3}{11} = \frac{3}{11} [/tex]
[tex]3 \frac{4}{7} \times \frac{2}{5} = \frac{25}{7} \times \frac{2}{5} = \frac{5}{7} \times \frac{2}{1} = \frac{10}{7} = 1 \frac{3}{7} [/tex]