[tex]dane:\\p = 120 \ hPa = 120\times100 \ Pa = 12 \ 000 \ Pa =12 \ 000 \ \frac{N}{m^{2}}\\d = 1000\frac{kg}{m^{3}} \ - \ gestosc \ wody\\g = 10\frac{N}{kg}\\Szukane:\\h = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h \ \ |:(d\cdot g)\\\\h = \frac{p}{d\cdot g}\\\\h = \frac{12000 \ Pa}{1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}}=\frac{12000 \ \frac{N}{m^{2}}}{10000\frac{N}{m^{3}}}\\\\\boxed{h = 1,2 \ m}[/tex]
Odp. Szukana głębokość h = 1,2 m.
