a)
h - wysokość ściany bocznej
[tex]Pc = Pp+4Pb\\Pp = 16^2=256\\h^2 = 20^2-8^2\\h^2 = 400-64 = 336\\h=4\sqrt{21} \\Pb = \frac{16*4\sqrt{21} }{2} =32\sqrt{21}\\Pc = 256 + 4*32\sqrt{21} = 256 + 128\sqrt{21}[/tex]
b)
[tex]Pc = Pp + 3Pb\\Pp = \frac{30^2\sqrt{3} }{4} =225\sqrt{3} \\h^2 = 25^2-15^2\\h^2 = 625-225=400\\h=20\\Pb = \frac{30*20}{2} =300\\Pc = 225\sqrt{3} +3*300=225\sqrt3+900[/tex]
