Odpowiedź:
[tex]k)\ \ (-2\frac{2}{3}):1,2=-\frac{8}{3}:\frac{12}{10}=-\frac{8}{3}:\frac{6}{5}=-\frac{\not8^4}{3}\cdot\frac{5}{\not6_{3}}=-\frac{4}{3}\cdot\frac{5}{3}=-\frac{20}{9}=-2\frac{2}{9}\\\\\\l)\ \ \frac{2}{3}:(-6)=\frac{\not2^1}{3}\cdot(-\frac{1}{\not6_{3}})=\frac{1}{3}\cdot(-\frac{1}{3})=-\frac{1}{9}\\\\\\m)\ \ (-0,45):1\frac{4}{5}=-\frac{45}{100}:\frac{9}{5}=-\frac{\not9^1}{\not20_{4}}\cdot\frac{\not5^1}{\not9_{1}}=-\frac{1}{4}[/tex]
[tex]n)\ \ (-2,75):(-2,2)=2,75:2,2=1,25\\\\(-2,75):(-2,2)=2,75:2,2=\frac{275}{100}:\frac{22}{10}=\frac{11}{4}:\frac{11}{5}=\frac{\not11^1}{4}\cdot\frac{5}{\not11_{1}}=\frac{5}{4}=1\frac{1}{4}\\\\\\o)\ \ (-3,5):(-1\frac{2}{5})=3,5:1\frac{2}{5}=\frac{35}{10}:\frac{7}{5}=\frac{\not7^1}{2}\cdot\frac{5}{\not7_{1}}=\frac{5}{2}=2\frac{1}{2}[/tex]
Iloraz dwóch liczb ujemnych jest dodatni (-) : (-) = +
