Odpowiedź:
Wzór na przekątną kwadratu
[tex]d=a\sqrt{2}[/tex]
[tex]Obliczamy\ \ bok\ \ kwadratu\\\\d=a\sqrt{2}\\\\20=a\sqrt{2}\\\\a\sqrt{2}=20\ \ /:\sqrt{2}\\\\a=\frac{20}{\sqrt{2}}\\\\a=\frac{20}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{\not20^1^0\sqrt{2}}{\not2_{1}}=10\sqrt{2}m\\\\\\Obliczamy\ \ pole\\\\P=a^2\\\\P=(10\sqrt{2})^2=10^2\cdot(\sqrt{2})^2=100\cdot2=200m^2\\\\Odp.Pole\ \ kwadratu\ \ wynosi\ \ 200m^2[/tex]
