Odpowiedź:
a) 3(x - 2) - x = 2x + 1
3x - 6 - x = 2x + 1
3x - 2x - x = 6 + 1
0 [tex]\neq[/tex] 6
x = ∅
b) 2x - 5 = - 4x + 8
2x + 4x = 5 + 8
6x = 13 | : 6
x = [tex]2\frac{1}{6}[/tex]
c) -3( x - 4) > -2(3 - x)
-3x + 12 > -6 + 2x
-3x - 2x > -12 -6
-5x > -18 |: (- 5)
x < [tex]3\frac{3}{5}[/tex]
d) [tex](x + 2)^{2}[/tex] < [tex]x^{2}[/tex]
[tex]x^{2}[/tex] + 4x + 4 < [tex]x^{2}[/tex] | - [tex]x^{2}[/tex]
4x + 4 < 0 |- 4
4x < -4 |: 4
x <-1
Szczegółowe wyjaśnienie:
