Odpowiedź:
Na koncu dodaj sobie cm kwadratowe i cm szescienne.
V=Pp*H
Pc=2*Pp+Pb
a) ten trzeci bok
[tex]x^{2} = 13^{2}-5^{2} \\x^{2} =169-25\\x = \sqrt{144} \\x = 12[/tex]
Pp = 1/2*12*5 = 30
Pc = 2*30+ 5*5+13*5+12*5 = 60+25+65+60 = 120 + 90 = 210
V = 30*5 = 150
b)
wysokosc trapezu:
(8-2) / 2 = 3
[tex]x^{2} = 5^{2} -3^{2} \\x=\sqrt{16} \\x=4[/tex]
Pp = (2+8)*4/2 = 20
Pc = 2*20+2*5+5*2*5+8*5= 40 + 10 + 50 + 40 = 140
V = 20*5 = 100
c)
wyoskosc trapezu:
12-4 = 8
[tex]x^{2} = 10^{2} - 8^{2} \\x^{2} = 36\\x=6[/tex]
Pp = (4+12)*6/2= 48
Pc = 2*48+10*5+4*5+12*5+6*5=96+50+20+60+30 =160+96 = 256
V = 48*5=240
Szczegółowe wyjaśnienie:
