Odpowiedź:
[tex]b)\ \ \dfrac{3\sqrt{5}\cdot\sqrt{6}}{2\sqrt{2}}=\dfrac{3\sqrt{5}\cdot\sqrt{3}}{2}=\dfrac{3\sqrt{15}}{2}\\\\\\d)\ \ \sqrt[3]{\frac{1}{3}}\cdot2\sqrt[3]{6}=2\sqrt[3]{\frac{1}{\not3_{1}}\cdot\not6^2}=2\sqrt[3]{2}\\\\\\f)\ \ 1-\dfrac{3\sqrt{5}}{\sqrt{125}}=1-\dfrac{3}{\sqrt{25}}=1-\frac{3}{5}=\frac{5}{5}-\frac{3}{5}=\frac{2}{5}[/tex]
[tex]h)\ \ \dfrac{\sqrt{0,8}:\sqrt{0,008}}{(-0,1)^2}=\dfrac{\sqrt{0,8:0,008}}{0,01}=\dfrac{\sqrt{100}}{0,01}=\dfrac{10}{0,01}=1000[/tex]
