[tex]Dane:\\p = 1 \ hPa = 100 \ Pa = 100 \ \frac{N}{m^{2}}\\d = 1000\frac{kg}{m^{3}} \ - \ gestosc \ wody\\g = 10\frac{N}{kg}\\Szukane:\\h = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h \ \ /:(d\cdot g)\\\\h = \frac{p}{d\cdot g}\\\\h = \frac{100 \ Pa}{1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}} =\frac{100\frac{N}{m^{2}}}{10000\frac{N}{m^{3}}}\\\\\boxed{h = 0,01 \ m = 1 cm}[/tex]
