Odpowiedź :
[tex]Dane:\\m = 250 \ g = 0,25 \ kg\\F = 20 \ N\\Szukane:\\a = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki \ Newtona\\\\a = \frac{F}{m}\\\\a =\frac{20 \ N}{0,25 \ kg} = \frac{20 \ kg\cdot\frac{m}{s^{2}}}{0,25 \ kg}\\\\\boxed{a = 80\frac{m}{s^{2}}}[/tex]