Odpowiedź :
CP
[tex] |CP { | }^{2} + {4}^{2} = {5}^{2} \\ { |CP| }^{2} + 16 = 25 \\ |CP| = \sqrt{25 - 16} \\ |CP| = \sqrt{9} \\ |CP| = 3[/tex]
DP
[tex]a \sqrt{2} = 3 \sqrt{2} \approx4.2[/tex]
AP
[tex] { |AP| }^{2} = {3}^{2} + (6 + 4 {)}^{2} \\ { |AP| }^{2} = 9 + {10}^{2} \\ { |AP| }^{2} = 9 + 100 \\ { |AP| }^{2} = 109 \\ AP = \sqrt{109} \approx10.4[/tex]
Najkrótszy jest odcinek |CP|