Odpowiedź :
a) 6^2 + x^2 = 12^2
x^2 = 144 - 36
x^2 = 108
x = v108
x = 6v3
b) 5^2 + y^2 = (3v7)^2
y^2 = 63 - 25
y^2 = 38
y = v38
x^2 = 144 - 36
x^2 = 108
x = v108
x = 6v3
b) 5^2 + y^2 = (3v7)^2
y^2 = 63 - 25
y^2 = 38
y = v38
Korzystamy z tw. Pitagorasa:
a² + b² = c²
gdzie:
a,b - przyprostkokątne,
c - przeciwprostokątna.
a)
[tex]x^{2}+6^{2} = 12^{2}\\\\x^{2} + 36 = 144\\\\x^{2} = 144 -36 = 108\\\\x = \sqrt{108} = \sqrt{36\cdot3}\\\\\boxed{x =6\sqrt{3}}[/tex]
b)
[tex]y^{2}+5^{2} = (3\sqrt{7})^{2}\\\\y^{2}+25 = 63\\\\y^{2} = 63-25 = 38\\\\\boxed{y = \sqrt{38}}[/tex]