Odpowiedź:
[tex](\frac{2}{3})^9:(\frac{4}{9})^6=(\frac{2}{3})^9:((\frac{2}{3})^2)^6=(\frac{2}{3})^9:(\frac{2}{3})^1^2=(\frac{2}{3})^{9-12}=(\frac{2}{3})^{-3}=(\frac{3}{2})^3=\frac{3^3}{2^3}=\\\\=\frac{27}{8}=3\frac{3}{8}[/tex]
