Odpowiedź:
[tex]\left\{ \begin{array}{l} 4(3x - \frac{1}{2}) - 5(y+\frac{1}{2}) = 9 \\ -2x - 5(y -2\frac{1}{2}) = - 9y + \frac{11}{2} \end{array}[/tex]
[tex]\left\{ \begin{array}{l} 12x - 2 - 5y-\frac{5}{2} = 9 \\ -2x - 5y +\frac{25}{2} = - 9y + \frac{11}{2} \end{array}[/tex]
[tex]\left\{ \begin{array}{l} 12x - 5y = \frac{27}{2} \\ -2x + 4y = -7 \end{array}[/tex]
[tex]\left\{ \begin{array}{l} 12x - 5y = 13,5 \\ -2x + 4y = -7 \end{array}[/tex]
-2x + 4y = - 7
-2x = - 7 - 4y
x = 3,5 + 2y
12x - 5y = 13,5
12*(3,5 + 2y) - 5y = 13,5
42 + 24y - 5y = 13,5
19y = - 28,5
[tex]y = -\frac{285}{190} = -\frac{3}{2}[/tex]
-2x + 4y = - 7
[tex]-2x + 4*(-\frac{3}{2}) = -7[/tex]
[tex]-2x -\frac{12}{2} = -7[/tex]
-2x = - 1
[tex]x = \frac{1}{2}[/tex]
[tex]\left\{ \begin{array}{l} x = \frac{1}{2} \\\\ y = -\frac{3}{2} \end{array}[/tex]
