[tex] {b}^{2} = {h}^{2} + ( \frac{1}{2} a \sqrt{2} {)}^{2} [/tex]
[tex]b = 5 \\ \\ \frac{1}{2} a \sqrt{2} = \frac{1}{2} \times 5 \sqrt{2} = 2.5 \sqrt{2} [/tex]
Wysokość ma
[tex] {5}^{2} = {h}^{2} + (2.5 \sqrt{2} {)}^{2} \\ 25 = {h}^{2} + 2. {5}^{2} \times 2 \\ 25 = {h}^{2} +( \frac{5}{2} {)}^{2} \times 2 \\ 25 = {h}^{2} + \frac{25}{4} \times 2 \\ 25 = {h}^{2} + \frac{50}{4} \\ 25 = {h}^{2} + 12.5 \\ {h}^{2} = 12.5 \\ \boxed{h = \sqrt{12.5}} [/tex]
