Odpowiedź:
[tex]P_{I} = P_{IV}\\\\P_{II} = P_{III}[/tex]
Szczegółowe wyjaśnienie:
[tex]P = \frac{1}{2}d_1d_2\sin\alpha\\\\\alpha = 90^{o} \ \ \rightarrow \ \ sin90^{o} = 1\\\\P=\frac{1}{2}d_1\cdot d_2\\\\\\I.\\\\P_{I} = \frac{1}{2}\cdot(3+8)\cdot(3+8) =\frac{1}{2}\cdot11^{2}\\\\\\II.\\\\P_{II} = \frac{1}{2}\cdot(5+10)\cdot(5+10) = \frac{1}{2}\cdot15^{2}\\\\\\III.\\\\P_{III} = \frac{1}{2}\cdot(9+6)\cdot(9+6) = \frac{1}{2}\cdot15^{2}\\\\\\IV.\\\\P_{IV} = \frac{1}{2}\cdot(4+7)\cdot(4+7) = \frac{1}{2}\cdot11^{2}[/tex]
