[tex]V = Pp \times H[/tex]
Pole podstawy
[tex]Pp = 6 \times \frac{ {8}^{2} \sqrt{3} }{4} = 6 \times \frac{64 \sqrt{3} }{4} = 6 \times 16 \sqrt{3} = \underline{96 \sqrt{3} {cm}^{2} }[/tex]
Objętość
[tex]V = 96 \sqrt{3} \times 5 = \boxed{ \underline{ \bold{480 \sqrt{3} {cm}^{3} }}}[/tex]
