Bok rombu
[tex] {4}^{2} + {6}^{2} = {x}^{2} \\ 16 + 36 = {x}^{2} \\ {x}^{2} = 52 \\ x = \sqrt{52} \\ x = \sqrt{4 \times 13} \\ x = 2 \sqrt{13} [/tex]
Obwód
[tex]4 \times 2 \sqrt{13} = 8 \sqrt{13} [/tex]
Pole
[tex] \frac{8 \times 12}{2} = 4 \times 12 = 48[/tex]
